WebNov 17, 2014 · Using String string=new String (); is strongly discouraged. StringBuffer stringbuffer=new StringBuffer (): //you can use StringBuilder here Scanner input=new Scanner (System.in); System.out.println ("Enter a String"); stringbuffer.append (input.nextLine ()); Share Improve this answer Follow answered Nov 17, 2014 at 5:22 … WebMar 23, 2024 · Using the Scanner method: useDelimiter(String pattern) Using the Scanner method : useDelimiter(Pattern pattern) where Pattern is a regular expression that specifies the delimiter set. So useDelimiter() methods are used to tokenize the Scanner input, and behave like StringTokenizer class, take a look at these tutorials for further information:
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WebSep 15, 2016 · import java.util.Scanner; public class Main { public static void main (String [] args) { Scanner scanner = new Scanner (System.in).useDelimiter ("\n"); String input = scanner.next (); System.out.println (input); scanner.close (); } } Share Improve this answer Follow answered Oct 3, 2024 at 7:05 Rajesh 4,083 1 31 32 Add a comment 12 WebJan 9, 2024 · String s = "HackerRank "; Scanner scan = new Scanner (System.in); String s2; scan.nextLine (); // read the rest of the line of input (newline character after the double token). s2 = scan.nextLine (); /* Concatenate and print the String variables on a new line integer variables on a new line; System.out.println (s + s2); scan.close (); … teams screen share looks blurry
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Webimport java.util.Scanner; public class NameSorting { public static void main (String [] args) { Scanner s = new Scanner (System.in); String [] array = new String [20]; System.out.println ("Please enter 20 names to sort"); Scanner s1 = new Scanner (System.in); for (int i = 0; i < 0;) { array [i] = s1.nextLine (); } //Just to test … WebThe following are some techniques that we can use to take the String input in Java: 1. Using Scanner class nextLine () method 2. Using Scanner class next () method 3. Using … WebAug 30, 2013 · You may use one of input.nextXXX () as detailed in Scanner javadoc. to resolve compiler error in your case you may use input.nextLine (); get entire line of text. By Default whitespace delimiter used by a scanner. However If you need to scan sequence of inputs separated by a delimiter useDelimiter can be used to set regex delim space song markiplier